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1053521481113 is a prime number
BaseRepresentation
bin11110101010010101100…
…01100000110110011001
310201201022201112101001022
433111022301200312121
5114230102444343423
62123551525332225
7136054146556403
oct17251261406631
93651281471038
101053521481113
11376883457912
1215021a267075
13784677864aa
1438dc2727b73
151c61035cdc8
hexf54ac60d99

1053521481113 has 2 divisors, whose sum is σ = 1053521481114. Its totient is φ = 1053521481112.

The previous prime is 1053521481107. The next prime is 1053521481149. The reversal of 1053521481113 is 3111841253501.

1053521481113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1035434458969 + 18087022144 = 1017563^2 + 134488^2 .

It is a cyclic number.

It is not a de Polignac number, because 1053521481113 - 24 = 1053521481097 is a prime.

It is a super-2 number, since 2×10535214811132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1053521481413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526760740556 + 526760740557.

It is an arithmetic number, because the mean of its divisors is an integer number (526760740557).

Almost surely, 21053521481113 is an apocalyptic number.

It is an amenable number.

1053521481113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1053521481113 is an equidigital number, since it uses as much as digits as its factorization.

1053521481113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 35.

The spelling of 1053521481113 in words is "one trillion, fifty-three billion, five hundred twenty-one million, four hundred eighty-one thousand, one hundred thirteen".