Base | Representation |
---|---|
bin | 11110101010100110011… |
… | …10101101110010100001 |
3 | 10201201200121111021002022 |
4 | 33111103032231302201 |
5 | 114230400304312032 |
6 | 2124013554231225 |
7 | 136060521510131 |
oct | 17252316556241 |
9 | 3651617437068 |
10 | 1053663354017 |
11 | 37694654904a |
12 | 150259885515 |
13 | 7848ac9b161 |
14 | 38dd74d8ac1 |
15 | 1c61ca34512 |
hex | f5533adca1 |
1053663354017 has 2 divisors, whose sum is σ = 1053663354018. Its totient is φ = 1053663354016.
The previous prime is 1053663353983. The next prime is 1053663354031. The reversal of 1053663354017 is 7104533663501.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 779505346816 + 274158007201 = 882896^2 + 523601^2 .
It is a cyclic number.
It is not a de Polignac number, because 1053663354017 - 220 = 1053662305441 is a prime.
It is a super-2 number, since 2×10536633540172 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1053663344017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526831677008 + 526831677009.
It is an arithmetic number, because the mean of its divisors is an integer number (526831677009).
Almost surely, 21053663354017 is an apocalyptic number.
It is an amenable number.
1053663354017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1053663354017 is an equidigital number, since it uses as much as digits as its factorization.
1053663354017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 680400, while the sum is 44.
The spelling of 1053663354017 in words is "one trillion, fifty-three billion, six hundred sixty-three million, three hundred fifty-four thousand, seventeen".
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