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1053775354153 is a prime number
BaseRepresentation
bin11110101010110011110…
…01111101100100101001
310201201222102020110101111
433111121321331210221
5114231112442313103
62124033034550321
7136063351502134
oct17253171754451
93651872213344
101053775354153
113769a3796445
1215028b2983a1
13784a8253a22
143900833121b
151c6277a986d
hexf559e7d929

1053775354153 has 2 divisors, whose sum is σ = 1053775354154. Its totient is φ = 1053775354152.

The previous prime is 1053775354147. The next prime is 1053775354207. The reversal of 1053775354153 is 3514535773501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 702064679449 + 351710674704 = 837893^2 + 593052^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1053775354153 is a prime.

It is a super-2 number, since 2×10537753541532 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1053775354097 and 1053775354106.

It is not a weakly prime, because it can be changed into another prime (1023775354153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526887677076 + 526887677077.

It is an arithmetic number, because the mean of its divisors is an integer number (526887677077).

Almost surely, 21053775354153 is an apocalyptic number.

It is an amenable number.

1053775354153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1053775354153 is an equidigital number, since it uses as much as digits as its factorization.

1053775354153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3307500, while the sum is 49.

The spelling of 1053775354153 in words is "one trillion, fifty-three billion, seven hundred seventy-five million, three hundred fifty-four thousand, one hundred fifty-three".