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1054021433 is a prime number
BaseRepresentation
bin111110110100110…
…001011100111001
32201110022211120212
4332310301130321
54124312141213
6252331200505
735056014533
oct7664613471
92643284525
101054021433
114a0a709a3
12254ba6135
1313a4a2b2a
149ddb0853
15628029a8
hex3ed31739

1054021433 has 2 divisors, whose sum is σ = 1054021434. Its totient is φ = 1054021432.

The previous prime is 1054021427. The next prime is 1054021459. The reversal of 1054021433 is 3341204501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 706124329 + 347897104 = 26573^2 + 18652^2 .

It is a cyclic number.

It is not a de Polignac number, because 1054021433 - 220 = 1052972857 is a prime.

It is a super-2 number, since 2×10540214332 = 2221922362446746978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1054021399 and 1054021408.

It is not a weakly prime, because it can be changed into another prime (1054021933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527010716 + 527010717.

It is an arithmetic number, because the mean of its divisors is an integer number (527010717).

Almost surely, 21054021433 is an apocalyptic number.

It is an amenable number.

1054021433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1054021433 is an equidigital number, since it uses as much as digits as its factorization.

1054021433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 1054021433 is about 32465.6962500421. The cubic root of 1054021433 is about 1017.6922815142.

Adding to 1054021433 its reverse (3341204501), we get a palindrome (4395225934).

The spelling of 1054021433 in words is "one billion, fifty-four million, twenty-one thousand, four hundred thirty-three".