Base | Representation |
---|---|
bin | 11110101011100000111… |
… | …00010010011001100011 |
3 | 10201202221202200202220101 |
4 | 33111300130102121203 |
5 | 114232401240413412 |
6 | 2124134342523231 |
7 | 136105622330461 |
oct | 17256034223143 |
9 | 3652852622811 |
10 | 1054153451107 |
11 | 377078161269 |
12 | 150375a36517 |
13 | 78538696933 |
14 | 39042633831 |
15 | 1c64aa93457 |
hex | f570712663 |
1054153451107 has 2 divisors, whose sum is σ = 1054153451108. Its totient is φ = 1054153451106.
The previous prime is 1054153451033. The next prime is 1054153451161. The reversal of 1054153451107 is 7011543514501.
1054153451107 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1054153451107 - 231 = 1052005967459 is a prime.
It is a super-2 number, since 2×10541534511072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1054153451167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527076725553 + 527076725554.
It is an arithmetic number, because the mean of its divisors is an integer number (527076725554).
Almost surely, 21054153451107 is an apocalyptic number.
1054153451107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1054153451107 is an equidigital number, since it uses as much as digits as its factorization.
1054153451107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42000, while the sum is 37.
Adding to 1054153451107 its reverse (7011543514501), we get a palindrome (8065696965608).
The spelling of 1054153451107 in words is "one trillion, fifty-four billion, one hundred fifty-three million, four hundred fifty-one thousand, one hundred seven".
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