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1054310112017 is a prime number
BaseRepresentation
bin11110101011110011100…
…01111001101100010001
310201210100200110222021022
433111321301321230101
5114233211342041032
62124202100405225
7136112534042021
oct17257161715421
93653320428238
101054310112017
11377148632998
121503ba3a6815
1378561c885b6
1439059373a81
151c6596db512
hexf579c79b11

1054310112017 has 2 divisors, whose sum is σ = 1054310112018. Its totient is φ = 1054310112016.

The previous prime is 1054310111989. The next prime is 1054310112029. The reversal of 1054310112017 is 7102110134501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 816789367696 + 237520744321 = 903764^2 + 487361^2 .

It is a cyclic number.

It is not a de Polignac number, because 1054310112017 - 234 = 1037130242833 is a prime.

It is a super-3 number, since 3×10543101120173 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1054310112077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527155056008 + 527155056009.

It is an arithmetic number, because the mean of its divisors is an integer number (527155056009).

Almost surely, 21054310112017 is an apocalyptic number.

It is an amenable number.

1054310112017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1054310112017 is an equidigital number, since it uses as much as digits as its factorization.

1054310112017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 26.

Adding to 1054310112017 its reverse (7102110134501), we get a palindrome (8156420246518).

The spelling of 1054310112017 in words is "one trillion, fifty-four billion, three hundred ten million, one hundred twelve thousand, seventeen".