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105431134341 = 3135235168953
BaseRepresentation
bin110001000110000101…
…1110111000010000101
3101002010200021112221110
41202030023313002011
53211410332244331
6120233455035233
710421452566261
oct1421413670205
9332120245843
10105431134341
1140793143785
121852480bb19
139c32a90cc0
1451624ad0a1
152b20e54946
hex188c2f7085

105431134341 has 16 divisors (see below), whose sum is σ = 151677786176. Its totient is φ = 64756630656.

The previous prime is 105431134313. The next prime is 105431134351. The reversal of 105431134341 is 143431134501.

It is not a de Polignac number, because 105431134341 - 219 = 105430610053 is a prime.

It is a super-2 number, since 2×1054311343412 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 105431134299 and 105431134308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (105431134351) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2564080 + ... + 2604873.

It is an arithmetic number, because the mean of its divisors is an integer number (9479861636).

Almost surely, 2105431134341 is an apocalyptic number.

It is an amenable number.

105431134341 is a deficient number, since it is larger than the sum of its proper divisors (46246651835).

105431134341 is a wasteful number, since it uses less digits than its factorization.

105431134341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5169492.

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 105431134341 its reverse (143431134501), we get a palindrome (248862268842).

The spelling of 105431134341 in words is "one hundred five billion, four hundred thirty-one million, one hundred thirty-four thousand, three hundred forty-one".

Divisors: 1 3 13 39 523 1569 6799 20397 5168953 15506859 67196389 201589167 2703362419 8110087257 35143711447 105431134341