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10543341842513 is a prime number
BaseRepresentation
bin1001100101101101000000…
…1001010011000001010001
31101022221012121202200200022
42121123100021103001101
52340220231002430023
634231313330233225
72135505560660564
oct231332011230121
941287177680608
1010543341842513
1133a5451673277
121223453a25815
135b63047cb24c
1428642c6ac4db
151343cab287c8
hex996d0253051

10543341842513 has 2 divisors, whose sum is σ = 10543341842514. Its totient is φ = 10543341842512.

The previous prime is 10543341842497. The next prime is 10543341842569. The reversal of 10543341842513 is 31524814334501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10269570116689 + 273771725824 = 3204617^2 + 523232^2 .

It is a cyclic number.

It is not a de Polignac number, because 10543341842513 - 24 = 10543341842497 is a prime.

It is a super-2 number, since 2×105433418425132 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (10543341842573) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5271670921256 + 5271670921257.

It is an arithmetic number, because the mean of its divisors is an integer number (5271670921257).

Almost surely, 210543341842513 is an apocalyptic number.

It is an amenable number.

10543341842513 is a deficient number, since it is larger than the sum of its proper divisors (1).

10543341842513 is an equidigital number, since it uses as much as digits as its factorization.

10543341842513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 691200, while the sum is 44.

The spelling of 10543341842513 in words is "ten trillion, five hundred forty-three billion, three hundred forty-one million, eight hundred forty-two thousand, five hundred thirteen".