Base | Representation |
---|---|
bin | 11110101011111110101… |
… | …10001010110010011011 |
3 | 10201210121012012211210001 |
4 | 33111333112022302123 |
5 | 114233404244132212 |
6 | 2124215234233431 |
7 | 136115046626455 |
oct | 17257726126233 |
9 | 3653535184701 |
10 | 1054403505307 |
11 | 377196321729 |
12 | 150425725877 |
13 | 78578427bb9 |
14 | 390679252d5 |
15 | 1c6629d8657 |
hex | f57f58ac9b |
1054403505307 has 2 divisors, whose sum is σ = 1054403505308. Its totient is φ = 1054403505306.
The previous prime is 1054403505271. The next prime is 1054403505313. The reversal of 1054403505307 is 7035053044501.
It is a strong prime.
It is an emirp because it is prime and its reverse (7035053044501) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1054403505307 - 27 = 1054403505179 is a prime.
It is a super-2 number, since 2×10544035053072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1054403509307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527201752653 + 527201752654.
It is an arithmetic number, because the mean of its divisors is an integer number (527201752654).
Almost surely, 21054403505307 is an apocalyptic number.
1054403505307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1054403505307 is an equidigital number, since it uses as much as digits as its factorization.
1054403505307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 126000, while the sum is 37.
Adding to 1054403505307 its reverse (7035053044501), we get a palindrome (8089456549808).
The spelling of 1054403505307 in words is "one trillion, fifty-four billion, four hundred three million, five hundred five thousand, three hundred seven".
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