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105442307 is a prime number
BaseRepresentation
bin1100100100011…
…10110000000011
321100102000122122
412102032300003
5203443123212
614243554455
72420146655
oct622166003
9240360578
10105442307
1154579403
122b38ba2b
1318aca9c9
141000a6d5
1593cc272
hex648ec03

105442307 has 2 divisors, whose sum is σ = 105442308. Its totient is φ = 105442306.

The previous prime is 105442301. The next prime is 105442319. The reversal of 105442307 is 703244501.

It is a weak prime.

It is an emirp because it is prime and its reverse (703244501) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 105442307 - 224 = 88665091 is a prime.

It is a super-2 number, since 2×1054423072 = 22236160210964498, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (105442301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52721153 + 52721154.

It is an arithmetic number, because the mean of its divisors is an integer number (52721154).

Almost surely, 2105442307 is an apocalyptic number.

105442307 is a deficient number, since it is larger than the sum of its proper divisors (1).

105442307 is an equidigital number, since it uses as much as digits as its factorization.

105442307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3360, while the sum is 26.

The square root of 105442307 is about 10268.5104567313. The cubic root of 105442307 is about 472.4309046711.

Adding to 105442307 its reverse (703244501), we get a palindrome (808686808).

The spelling of 105442307 in words is "one hundred five million, four hundred forty-two thousand, three hundred seven".