Base | Representation |
---|---|
bin | 11110101101010011000… |
… | …01110100001011111111 |
3 | 10201212102111212112111110 |
4 | 33112221201310023333 |
5 | 114241331431422120 |
6 | 2124413354453103 |
7 | 136141432143666 |
oct | 17265141641377 |
9 | 3655374775443 |
10 | 1055111201535 |
11 | 377519848346 |
12 | 1505a2734193 |
13 | 7865bc30371 |
14 | 390d3903ddd |
15 | 1c6a4bcb2e0 |
hex | f5a98742ff |
1055111201535 has 16 divisors (see below), whose sum is σ = 1694903736960. Its totient is φ = 560484036000.
The previous prime is 1055111201513. The next prime is 1055111201561. The reversal of 1055111201535 is 5351021115501.
It is not a de Polignac number, because 1055111201535 - 25 = 1055111201503 is a prime.
It is a super-2 number, since 2×10551112015352 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 140117245 + ... + 140124774.
It is an arithmetic number, because the mean of its divisors is an integer number (105931483560).
Almost surely, 21055111201535 is an apocalyptic number.
1055111201535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1055111201535 is a deficient number, since it is larger than the sum of its proper divisors (639792535425).
1055111201535 is a wasteful number, since it uses less digits than its factorization.
1055111201535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 280242278.
The product of its (nonzero) digits is 3750, while the sum is 30.
The spelling of 1055111201535 in words is "one trillion, fifty-five billion, one hundred eleven million, two hundred one thousand, five hundred thirty-five".
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