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1055243314897 is a prime number
BaseRepresentation
bin11110101101100010110…
…01110010011011010001
310201212202201110120221221
433112301121302123101
5114242114242034042
62124434434245041
7136144625116102
oct17266131623321
93655681416857
101055243314897
11377587383042
1215061aa26781
1378680408a55
14391072943a9
151c6b15c5d67
hexf5b16726d1

1055243314897 has 2 divisors, whose sum is σ = 1055243314898. Its totient is φ = 1055243314896.

The previous prime is 1055243314891. The next prime is 1055243314919. The reversal of 1055243314897 is 7984133425501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 985907999041 + 69335315856 = 992929^2 + 263316^2 .

It is a cyclic number.

It is not a de Polignac number, because 1055243314897 - 235 = 1020883576529 is a prime.

It is a super-2 number, since 2×10552433148972 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1055243314891) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527621657448 + 527621657449.

It is an arithmetic number, because the mean of its divisors is an integer number (527621657449).

Almost surely, 21055243314897 is an apocalyptic number.

It is an amenable number.

1055243314897 is a deficient number, since it is larger than the sum of its proper divisors (1).

1055243314897 is an equidigital number, since it uses as much as digits as its factorization.

1055243314897 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3628800, while the sum is 52.

The spelling of 1055243314897 in words is "one trillion, fifty-five billion, two hundred forty-three million, three hundred fourteen thousand, eight hundred ninety-seven".