Base | Representation |
---|---|
bin | 11110101101100010110… |
… | …01110010011011010001 |
3 | 10201212202201110120221221 |
4 | 33112301121302123101 |
5 | 114242114242034042 |
6 | 2124434434245041 |
7 | 136144625116102 |
oct | 17266131623321 |
9 | 3655681416857 |
10 | 1055243314897 |
11 | 377587383042 |
12 | 15061aa26781 |
13 | 78680408a55 |
14 | 391072943a9 |
15 | 1c6b15c5d67 |
hex | f5b16726d1 |
1055243314897 has 2 divisors, whose sum is σ = 1055243314898. Its totient is φ = 1055243314896.
The previous prime is 1055243314891. The next prime is 1055243314919. The reversal of 1055243314897 is 7984133425501.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 985907999041 + 69335315856 = 992929^2 + 263316^2 .
It is a cyclic number.
It is not a de Polignac number, because 1055243314897 - 235 = 1020883576529 is a prime.
It is a super-2 number, since 2×10552433148972 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1055243314891) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527621657448 + 527621657449.
It is an arithmetic number, because the mean of its divisors is an integer number (527621657449).
Almost surely, 21055243314897 is an apocalyptic number.
It is an amenable number.
1055243314897 is a deficient number, since it is larger than the sum of its proper divisors (1).
1055243314897 is an equidigital number, since it uses as much as digits as its factorization.
1055243314897 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3628800, while the sum is 52.
The spelling of 1055243314897 in words is "one trillion, fifty-five billion, two hundred forty-three million, three hundred fourteen thousand, eight hundred ninety-seven".
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