Base | Representation |
---|---|
bin | 11110101101111101000… |
… | …00010101011010100001 |
3 | 10201220100001002121021211 |
4 | 33112332200111122201 |
5 | 114243042030304011 |
6 | 2124512325550121 |
7 | 136153234422511 |
oct | 17267640253241 |
9 | 3656301077254 |
10 | 1055463134881 |
11 | 37768a473051 |
12 | 150680575341 |
13 | 786b6b1254c |
14 | 39128555841 |
15 | 1c6c5a47b21 |
hex | f5be8156a1 |
1055463134881 has 2 divisors, whose sum is σ = 1055463134882. Its totient is φ = 1055463134880.
The previous prime is 1055463134797. The next prime is 1055463134911. The reversal of 1055463134881 is 1884313645501.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 940327787025 + 115135347856 = 969705^2 + 339316^2 .
It is a cyclic number.
It is not a de Polignac number, because 1055463134881 - 223 = 1055454746273 is a prime.
It is a super-2 number, since 2×10554631348812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1055463134581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527731567440 + 527731567441.
It is an arithmetic number, because the mean of its divisors is an integer number (527731567441).
Almost surely, 21055463134881 is an apocalyptic number.
It is an amenable number.
1055463134881 is a deficient number, since it is larger than the sum of its proper divisors (1).
1055463134881 is an equidigital number, since it uses as much as digits as its factorization.
1055463134881 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1382400, while the sum is 49.
The spelling of 1055463134881 in words is "one trillion, fifty-five billion, four hundred sixty-three million, one hundred thirty-four thousand, eight hundred eighty-one".
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