Search a number
-
+
1055482418113 is a prime number
BaseRepresentation
bin11110101101111111010…
…01111001001111000001
310201220101101101021220121
433112333221321033001
5114243111444334423
62124514255140241
7136153560345034
oct17267751711701
93656341337817
101055482418113
1137769a343902
12150686b14681
13786bab04646
143912ad3501b
151c6c75a645d
hexf5bfa793c1

1055482418113 has 2 divisors, whose sum is σ = 1055482418114. Its totient is φ = 1055482418112.

The previous prime is 1055482418101. The next prime is 1055482418119. The reversal of 1055482418113 is 3118142845501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 879378813504 + 176103604609 = 937752^2 + 419647^2 .

It is an emirp because it is prime and its reverse (3118142845501) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1055482418113 - 213 = 1055482409921 is a prime.

It is a super-2 number, since 2×10554824181132 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1055482418113.

It is not a weakly prime, because it can be changed into another prime (1055482418119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527741209056 + 527741209057.

It is an arithmetic number, because the mean of its divisors is an integer number (527741209057).

Almost surely, 21055482418113 is an apocalyptic number.

It is an amenable number.

1055482418113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1055482418113 is an equidigital number, since it uses as much as digits as its factorization.

1055482418113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 153600, while the sum is 43.

The spelling of 1055482418113 in words is "one trillion, fifty-five billion, four hundred eighty-two million, four hundred eighteen thousand, one hundred thirteen".