Base | Representation |
---|---|
bin | 110001001001101011… |
… | …0010101110000100111 |
3 | 101002110001102201121211 |
4 | 1202103112111300213 |
5 | 3212132114302101 |
6 | 120253431052251 |
7 | 10424442302122 |
oct | 1422326256047 |
9 | 332401381554 |
10 | 105551322151 |
11 | 40844a73650 |
12 | 18558b11087 |
13 | 9c51952552 |
14 | 51744373b9 |
15 | 2b2b795c51 |
hex | 1893595c27 |
105551322151 has 16 divisors (see below), whose sum is σ = 121973499648. Its totient is φ = 90271843200.
The previous prime is 105551322143. The next prime is 105551322157. The reversal of 105551322151 is 151223155501.
It is not a de Polignac number, because 105551322151 - 23 = 105551322143 is a prime.
It is a super-2 number, since 2×1055513221512 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (105551322157) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 310036 + ... + 554278.
It is an arithmetic number, because the mean of its divisors is an integer number (7623343728).
Almost surely, 2105551322151 is an apocalyptic number.
105551322151 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
105551322151 is a deficient number, since it is larger than the sum of its proper divisors (16422177497).
105551322151 is a wasteful number, since it uses less digits than its factorization.
105551322151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 246582.
The product of its (nonzero) digits is 7500, while the sum is 31.
Adding to 105551322151 its reverse (151223155501), we get a palindrome (256774477652).
The spelling of 105551322151 in words is "one hundred five billion, five hundred fifty-one million, three hundred twenty-two thousand, one hundred fifty-one".
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