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105551322143 is a prime number
BaseRepresentation
bin110001001001101011…
…0010101110000011111
3101002110001102201121112
41202103112111300133
53212132114302033
6120253431052235
710424442302111
oct1422326256037
9332401381545
10105551322143
1140844a73643
1218558b1107b
139c51952547
1451744373b1
152b2b795c48
hex1893595c1f

105551322143 has 2 divisors, whose sum is σ = 105551322144. Its totient is φ = 105551322142.

The previous prime is 105551322119. The next prime is 105551322157. The reversal of 105551322143 is 341223155501.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-105551322143 is a prime.

It is a super-2 number, since 2×1055513221432 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (105551322043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52775661071 + 52775661072.

It is an arithmetic number, because the mean of its divisors is an integer number (52775661072).

Almost surely, 2105551322143 is an apocalyptic number.

105551322143 is a deficient number, since it is larger than the sum of its proper divisors (1).

105551322143 is an equidigital number, since it uses as much as digits as its factorization.

105551322143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 105551322143 its reverse (341223155501), we get a palindrome (446774477644).

The spelling of 105551322143 in words is "one hundred five billion, five hundred fifty-one million, three hundred twenty-two thousand, one hundred forty-three".