Search a number
-
+
105551322313 is a prime number
BaseRepresentation
bin110001001001101011…
…0010101110011001001
3101002110001102201211211
41202103112111303021
53212132114303223
6120253431053121
710424442302443
oct1422326256311
9332401381754
10105551322313
1140844a73788
1218558b111a1
139c51952648
145174437493
152b2b795d0d
hex1893595cc9

105551322313 has 2 divisors, whose sum is σ = 105551322314. Its totient is φ = 105551322312.

The previous prime is 105551322277. The next prime is 105551322323. The reversal of 105551322313 is 313223155501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105347632329 + 203689984 = 324573^2 + 14272^2 .

It is an emirp because it is prime and its reverse (313223155501) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-105551322313 is a prime.

It is a super-2 number, since 2×1055513223132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (105551322323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52775661156 + 52775661157.

It is an arithmetic number, because the mean of its divisors is an integer number (52775661157).

Almost surely, 2105551322313 is an apocalyptic number.

It is an amenable number.

105551322313 is a deficient number, since it is larger than the sum of its proper divisors (1).

105551322313 is an equidigital number, since it uses as much as digits as its factorization.

105551322313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 105551322313 its reverse (313223155501), we get a palindrome (418774477814).

The spelling of 105551322313 in words is "one hundred five billion, five hundred fifty-one million, three hundred twenty-two thousand, three hundred thirteen".