Base | Representation |
---|---|
bin | 110001001001110011… |
… | …0011111010001001011 |
3 | 101002110100101210112221 |
4 | 1202103212133101023 |
5 | 3212134210233103 |
6 | 120254101514511 |
7 | 10424523263014 |
oct | 1422346372113 |
9 | 332410353487 |
10 | 105555555403 |
11 | 408473a5101 |
12 | 1855a412a37 |
13 | 9c527a532c |
14 | 5174c1a00b |
15 | 2b2bd301bd |
hex | 189399f44b |
105555555403 has 2 divisors, whose sum is σ = 105555555404. Its totient is φ = 105555555402.
The previous prime is 105555555397. The next prime is 105555555433. The reversal of 105555555403 is 304555555501.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 105555555403 - 213 = 105555547211 is a prime.
It is a super-2 number, since 2×1055555554032 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 105555555403.
It is not a weakly prime, because it can be changed into another prime (105555555433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52777777701 + 52777777702.
It is an arithmetic number, because the mean of its divisors is an integer number (52777777702).
Almost surely, 2105555555403 is an apocalyptic number.
105555555403 is a deficient number, since it is larger than the sum of its proper divisors (1).
105555555403 is an equidigital number, since it uses as much as digits as its factorization.
105555555403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 937500, while the sum is 43.
The spelling of 105555555403 in words is "one hundred five billion, five hundred fifty-five million, five hundred fifty-five thousand, four hundred three".
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