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1056025893907 is a prime number
BaseRepresentation
bin11110101111000000000…
…11000101110000010011
310201221210021000201112201
433113200003011300103
5114300220112101112
62125044231504031
7136203206664415
oct17274003056023
93657707021481
101056025893907
113779490a5256
121507b8b28017
137877659c35a
143917d1a69b5
151c70a15b257
hexf5e00c5c13

1056025893907 has 2 divisors, whose sum is σ = 1056025893908. Its totient is φ = 1056025893906.

The previous prime is 1056025893887. The next prime is 1056025893911. The reversal of 1056025893907 is 7093985206501.

It is a strong prime.

It is an emirp because it is prime and its reverse (7093985206501) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1056025893907 - 235 = 1021666155539 is a prime.

It is a super-2 number, since 2×10560258939072 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1056025893997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 528012946953 + 528012946954.

It is an arithmetic number, because the mean of its divisors is an integer number (528012946954).

Almost surely, 21056025893907 is an apocalyptic number.

1056025893907 is a deficient number, since it is larger than the sum of its proper divisors (1).

1056025893907 is an equidigital number, since it uses as much as digits as its factorization.

1056025893907 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4082400, while the sum is 55.

The spelling of 1056025893907 in words is "one trillion, fifty-six billion, twenty-five million, eight hundred ninety-three thousand, nine hundred seven".