Base | Representation |
---|---|
bin | 11110110110100111010… |
… | …10111011101011110011 |
3 | 10202100100010000111001111 |
4 | 33123103222323223303 |
5 | 114332102434430112 |
6 | 2131002001014151 |
7 | 136406410352314 |
oct | 17332352735363 |
9 | 3670303014044 |
10 | 1060113201907 |
11 | 3796562a1251 |
12 | 151559924357 |
13 | 78c7830c5b6 |
14 | 39449d6660b |
15 | 1c898dca5a7 |
hex | f6d3abbaf3 |
1060113201907 has 2 divisors, whose sum is σ = 1060113201908. Its totient is φ = 1060113201906.
The previous prime is 1060113201869. The next prime is 1060113201929. The reversal of 1060113201907 is 7091023110601.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1060113201907 - 27 = 1060113201779 is a prime.
It is a super-2 number, since 2×10601132019072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1060113211907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 530056600953 + 530056600954.
It is an arithmetic number, because the mean of its divisors is an integer number (530056600954).
Almost surely, 21060113201907 is an apocalyptic number.
1060113201907 is a deficient number, since it is larger than the sum of its proper divisors (1).
1060113201907 is an equidigital number, since it uses as much as digits as its factorization.
1060113201907 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2268, while the sum is 31.
The spelling of 1060113201907 in words is "one trillion, sixty billion, one hundred thirteen million, two hundred one thousand, nine hundred seven".
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