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10601827433 is a prime number
BaseRepresentation
bin10011101111110101…
…10000110001101001
31000100212012122011022
421313322300301221
5133203031434213
64512001542225
7523503021611
oct116772606151
930325178138
1010601827433
11455050095a
12207a644975
13ccc5a5a92
14728063a41
15420b3c308
hex277eb0c69

10601827433 has 2 divisors, whose sum is σ = 10601827434. Its totient is φ = 10601827432.

The previous prime is 10601827403. The next prime is 10601827441. The reversal of 10601827433 is 33472810601.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5812080169 + 4789747264 = 76237^2 + 69208^2 .

It is a cyclic number.

It is not a de Polignac number, because 10601827433 - 216 = 10601761897 is a prime.

It is a super-2 number, since 2×106018274332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10601827393 and 10601827402.

It is not a weakly prime, because it can be changed into another prime (10601827403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5300913716 + 5300913717.

It is an arithmetic number, because the mean of its divisors is an integer number (5300913717).

Almost surely, 210601827433 is an apocalyptic number.

It is an amenable number.

10601827433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10601827433 is an equidigital number, since it uses as much as digits as its factorization.

10601827433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 35.

The spelling of 10601827433 in words is "ten billion, six hundred one million, eight hundred twenty-seven thousand, four hundred thirty-three".