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1061006105993 is a prime number
BaseRepresentation
bin11110111000010001110…
…01000101110110001001
310202102122100011201012012
433130020321011312021
5114340420030342433
62131230335025305
7136440502045241
oct17341071056611
93672570151165
101061006105993
11379a74317309
1215176896b235
137908b2c0202
14394d2796b21
151c8ec4a4848
hexf708e45d89

1061006105993 has 2 divisors, whose sum is σ = 1061006105994. Its totient is φ = 1061006105992.

The previous prime is 1061006105983. The next prime is 1061006106019. The reversal of 1061006105993 is 3995016001601.

1061006105993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1016473289209 + 44532816784 = 1008203^2 + 211028^2 .

It is a cyclic number.

It is not a de Polignac number, because 1061006105993 - 210 = 1061006104969 is a prime.

It is a super-2 number, since 2×10610061059932 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1061006105993.

It is not a weakly prime, because it can be changed into another prime (1061006105933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 530503052996 + 530503052997.

It is an arithmetic number, because the mean of its divisors is an integer number (530503052997).

Almost surely, 21061006105993 is an apocalyptic number.

It is an amenable number.

1061006105993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1061006105993 is an equidigital number, since it uses as much as digits as its factorization.

1061006105993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43740, while the sum is 41.

The spelling of 1061006105993 in words is "one trillion, sixty-one billion, six million, one hundred five thousand, nine hundred ninety-three".