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10612016257147 is a prime number
BaseRepresentation
bin1001101001101100110101…
…1101011001100001111011
31101120111110122210102021121
42122123031131121201323
52342331402130212042
634323032025250111
72143456440606064
oct232331535314173
941514418712247
1010612016257147
113421592582448
12123481a933937
135bc92a420156
142898a522356b
15136099b93367
hex9a6cd75987b

10612016257147 has 2 divisors, whose sum is σ = 10612016257148. Its totient is φ = 10612016257146.

The previous prime is 10612016257099. The next prime is 10612016257181. The reversal of 10612016257147 is 74175261021601.

It is a strong prime.

It is an emirp because it is prime and its reverse (74175261021601) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10612016257147 - 215 = 10612016224379 is a prime.

It is a super-2 number, since 2×106120162571472 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10612016257547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5306008128573 + 5306008128574.

It is an arithmetic number, because the mean of its divisors is an integer number (5306008128574).

Almost surely, 210612016257147 is an apocalyptic number.

10612016257147 is a deficient number, since it is larger than the sum of its proper divisors (1).

10612016257147 is an equidigital number, since it uses as much as digits as its factorization.

10612016257147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 141120, while the sum is 43.

Adding to 10612016257147 its reverse (74175261021601), we get a palindrome (84787277278748).

The spelling of 10612016257147 in words is "ten trillion, six hundred twelve billion, sixteen million, two hundred fifty-seven thousand, one hundred forty-seven".