Base | Representation |
---|---|
bin | 110001011011100011… |
… | …1001100001010110111 |
3 | 101010222212110022022210 |
4 | 1202313013030022313 |
5 | 3214344220033422 |
6 | 120433143224503 |
7 | 10445346264426 |
oct | 1426707141267 |
9 | 333885408283 |
10 | 106151330487 |
11 | 41022727804 |
12 | 186a5a48133 |
13 | a019051b77 |
14 | 51cddc32bd |
15 | 2b642b610c |
hex | 18b71cc2b7 |
106151330487 has 32 divisors (see below), whose sum is σ = 152452800000. Its totient is φ = 65453488128.
The previous prime is 106151330479. The next prime is 106151330491. The reversal of 106151330487 is 784033151601.
It is not a de Polignac number, because 106151330487 - 23 = 106151330479 is a prime.
It is a super-3 number, since 3×1061513304873 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (106151330447) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15038463 + ... + 15045519.
It is an arithmetic number, because the mean of its divisors is an integer number (4764150000).
Almost surely, 2106151330487 is an apocalyptic number.
106151330487 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
106151330487 is a deficient number, since it is larger than the sum of its proper divisors (46301469513).
106151330487 is a wasteful number, since it uses less digits than its factorization.
106151330487 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12135.
The product of its (nonzero) digits is 60480, while the sum is 39.
The spelling of 106151330487 in words is "one hundred six billion, one hundred fifty-one million, three hundred thirty thousand, four hundred eighty-seven".
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