Base | Representation |
---|---|
bin | 1001101010011110001001… |
… | …0001000101100111111011 |
3 | 1101121202121221220002010112 |
4 | 2122213202101011213323 |
5 | 2343041003031101212 |
6 | 34333101135534535 |
7 | 2144435414662214 |
oct | 232474221054773 |
9 | 41552557802115 |
10 | 10625250253307 |
11 | 342716384a658 |
12 | 12372b298a44b |
13 | 5c0c59120001 |
14 | 28a39caa040b |
15 | 1365c1917422 |
hex | 9a9e24459fb |
10625250253307 has 2 divisors, whose sum is σ = 10625250253308. Its totient is φ = 10625250253306.
The previous prime is 10625250253253. The next prime is 10625250253357. The reversal of 10625250253307 is 70335205252601.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10625250253307 - 242 = 6227203742203 is a prime.
It is a super-2 number, since 2×106252502533072 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10625250253357) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5312625126653 + 5312625126654.
It is an arithmetic number, because the mean of its divisors is an integer number (5312625126654).
Almost surely, 210625250253307 is an apocalyptic number.
10625250253307 is a deficient number, since it is larger than the sum of its proper divisors (1).
10625250253307 is an equidigital number, since it uses as much as digits as its factorization.
10625250253307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 378000, while the sum is 41.
The spelling of 10625250253307 in words is "ten trillion, six hundred twenty-five billion, two hundred fifty million, two hundred fifty-three thousand, three hundred seven".
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