Base | Representation |
---|---|
bin | 10011110011100001… |
… | …11010101111000001 |
3 | 1000110000111021012111 |
4 | 21321300322233001 |
5 | 133233444114332 |
6 | 4515025455321 |
7 | 524330214313 |
oct | 117160725701 |
9 | 30400437174 |
10 | 10632801217 |
11 | 4566a36a25 |
12 | 2088aa1541 |
13 | 1005b2c06c |
14 | 72c2077b3 |
15 | 423709947 |
hex | 279c3abc1 |
10632801217 has 2 divisors, whose sum is σ = 10632801218. Its totient is φ = 10632801216.
The previous prime is 10632801163. The next prime is 10632801269. The reversal of 10632801217 is 71210823601.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8810450496 + 1822350721 = 93864^2 + 42689^2 .
It is an emirp because it is prime and its reverse (71210823601) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10632801217 - 27 = 10632801089 is a prime.
It is a super-2 number, since 2×106328012172 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10632801287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5316400608 + 5316400609.
It is an arithmetic number, because the mean of its divisors is an integer number (5316400609).
Almost surely, 210632801217 is an apocalyptic number.
It is an amenable number.
10632801217 is a deficient number, since it is larger than the sum of its proper divisors (1).
10632801217 is an equidigital number, since it uses as much as digits as its factorization.
10632801217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 31.
The spelling of 10632801217 in words is "ten billion, six hundred thirty-two million, eight hundred one thousand, two hundred seventeen".
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