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10642633105051 is a prime number
BaseRepresentation
bin1001101011011110111001…
…0111011001111010011011
31101200102111101210102220101
42122313232113121322123
52343332103033330201
634345054054440231
72145622240534243
oct232675627317233
941612441712811
1010642633105051
113433573a31432
12123a744363077
135c279952c5bc
1428b16b55cb23
15136c8ca16d01
hex9adee5d9e9b

10642633105051 has 2 divisors, whose sum is σ = 10642633105052. Its totient is φ = 10642633105050.

The previous prime is 10642633105019. The next prime is 10642633105073. The reversal of 10642633105051 is 15050133624601.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10642633105051 - 25 = 10642633105019 is a prime.

It is a super-3 number, since 3×106426331050513 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 10642633105051.

It is not a weakly prime, because it can be changed into another prime (10642633105751) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5321316552525 + 5321316552526.

It is an arithmetic number, because the mean of its divisors is an integer number (5321316552526).

Almost surely, 210642633105051 is an apocalyptic number.

10642633105051 is a deficient number, since it is larger than the sum of its proper divisors (1).

10642633105051 is an equidigital number, since it uses as much as digits as its factorization.

10642633105051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 37.

Adding to 10642633105051 its reverse (15050133624601), we get a palindrome (25692766729652).

The spelling of 10642633105051 in words is "ten trillion, six hundred forty-two billion, six hundred thirty-three million, one hundred five thousand, fifty-one".