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10643114033483 is a prime number
BaseRepresentation
bin1001101011100000101100…
…0010000000000101001011
31101200110201220202010200112
42122320023002000011023
52343334044143032413
634345213514424535
72145640200420041
oct232701302000513
941613656663615
1010643114033483
1134337a0452048
12123a85943214b
135c2845067a39
1428b1b538c391
15136cb9d642a8
hex9ae0b08014b

10643114033483 has 2 divisors, whose sum is σ = 10643114033484. Its totient is φ = 10643114033482.

The previous prime is 10643114033459. The next prime is 10643114033599. The reversal of 10643114033483 is 38433041134601.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10643114033483 - 238 = 10368236126539 is a prime.

It is a super-2 number, since 2×106431140334832 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10643114033483.

It is not a weakly prime, because it can be changed into another prime (10643114033983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5321557016741 + 5321557016742.

It is an arithmetic number, because the mean of its divisors is an integer number (5321557016742).

Almost surely, 210643114033483 is an apocalyptic number.

10643114033483 is a deficient number, since it is larger than the sum of its proper divisors (1).

10643114033483 is an equidigital number, since it uses as much as digits as its factorization.

10643114033483 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 248832, while the sum is 41.

The spelling of 10643114033483 in words is "ten trillion, six hundred forty-three billion, one hundred fourteen million, thirty-three thousand, four hundred eighty-three".