Base | Representation |
---|---|
bin | 1001101011100001011011… |
… | …0010100001101101010011 |
3 | 1101200111020122221111021201 |
4 | 2122320112302201231103 |
5 | 2343340000143203012 |
6 | 34345245242532031 |
7 | 2145645114244231 |
oct | 232702662415523 |
9 | 41614218844251 |
10 | 10643311303507 |
11 | 343389183aa23 |
12 | 123a8b3507017 |
13 | 5c2876ba756c |
14 | 28b1d365d951 |
15 | 136ccc32e857 |
hex | 9ae16ca1b53 |
10643311303507 has 2 divisors, whose sum is σ = 10643311303508. Its totient is φ = 10643311303506.
The previous prime is 10643311303459. The next prime is 10643311303519. The reversal of 10643311303507 is 70530311334601.
10643311303507 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10643311303507 - 231 = 10641163819859 is a prime.
It is a super-2 number, since 2×106433113035072 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10643311307507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5321655651753 + 5321655651754.
It is an arithmetic number, because the mean of its divisors is an integer number (5321655651754).
Almost surely, 210643311303507 is an apocalyptic number.
10643311303507 is a deficient number, since it is larger than the sum of its proper divisors (1).
10643311303507 is an equidigital number, since it uses as much as digits as its factorization.
10643311303507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 68040, while the sum is 37.
The spelling of 10643311303507 in words is "ten trillion, six hundred forty-three billion, three hundred eleven million, three hundred three thousand, five hundred seven".
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