Base | Representation |
---|---|
bin | 1001101011101010000100… |
… | …1100101000000111011011 |
3 | 1101200201020111101021121221 |
4 | 2122322201030220013123 |
5 | 2343404224122320212 |
6 | 34350311513312511 |
7 | 2146056501612532 |
oct | 232724114500733 |
9 | 41621214337557 |
10 | 10645633401307 |
11 | 3434873584413 |
12 | 123b241105737 |
13 | 5c2b56cb8928 |
14 | 28b373c01319 |
15 | 136db6118807 |
hex | 9aea13281db |
10645633401307 has 2 divisors, whose sum is σ = 10645633401308. Its totient is φ = 10645633401306.
The previous prime is 10645633401301. The next prime is 10645633401349. The reversal of 10645633401307 is 70310433654601.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10645633401307 is a prime.
It is a super-2 number, since 2×106456334013072 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10645633401301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5322816700653 + 5322816700654.
It is an arithmetic number, because the mean of its divisors is an integer number (5322816700654).
Almost surely, 210645633401307 is an apocalyptic number.
10645633401307 is a deficient number, since it is larger than the sum of its proper divisors (1).
10645633401307 is an equidigital number, since it uses as much as digits as its factorization.
10645633401307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 544320, while the sum is 43.
The spelling of 10645633401307 in words is "ten trillion, six hundred forty-five billion, six hundred thirty-three million, four hundred one thousand, three hundred seven".
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