Base | Representation |
---|---|
bin | 11111000110100001001… |
… | …10011101100111101011 |
3 | 10210011101011120201201222 |
4 | 33203100212131213223 |
5 | 120002044304230011 |
6 | 2134533133132255 |
7 | 140131120001645 |
oct | 17432046354753 |
9 | 3704334521658 |
10 | 1068651633131 |
11 | 382237a94a85 |
12 | 15314132a08b |
13 | 79a09272274 |
14 | 39a19d4b895 |
15 | 1cbe87d0ddb |
hex | f8d099d9eb |
1068651633131 has 2 divisors, whose sum is σ = 1068651633132. Its totient is φ = 1068651633130.
The previous prime is 1068651633121. The next prime is 1068651633149. The reversal of 1068651633131 is 1313361568601.
It is a weak prime.
It is an emirp because it is prime and its reverse (1313361568601) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1068651633131 - 222 = 1068647438827 is a prime.
It is a super-2 number, since 2×10686516331312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1068651633121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 534325816565 + 534325816566.
It is an arithmetic number, because the mean of its divisors is an integer number (534325816566).
Almost surely, 21068651633131 is an apocalyptic number.
1068651633131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1068651633131 is an equidigital number, since it uses as much as digits as its factorization.
1068651633131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 233280, while the sum is 44.
The spelling of 1068651633131 in words is "one trillion, sixty-eight billion, six hundred fifty-one million, six hundred thirty-three thousand, one hundred thirty-one".
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