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106885388654393 is a prime number
BaseRepresentation
bin11000010011011000110001…
…100111110101011100111001
3112000110010212111210220022212
4120103120301213311130321
5103002202233443420033
61015154245241224505
731341133400063636
oct3023306147653471
9460403774726285
10106885388654393
1131069925443188
12bba3130492135
134784330ab41bb
141c573cd65318d
15c55503141748
hex6136319f5739

106885388654393 has 2 divisors, whose sum is σ = 106885388654394. Its totient is φ = 106885388654392.

The previous prime is 106885388654381. The next prime is 106885388654413. The reversal of 106885388654393 is 393456883588601.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95493703879744 + 11391684774649 = 9772088^2 + 3375157^2 .

It is a cyclic number.

It is not a de Polignac number, because 106885388654393 - 212 = 106885388650297 is a prime.

It is a super-3 number, since 3×1068853886543933 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (106185388654393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53442694327196 + 53442694327197.

It is an arithmetic number, because the mean of its divisors is an integer number (53442694327197).

Almost surely, 2106885388654393 is an apocalyptic number.

It is an amenable number.

106885388654393 is a deficient number, since it is larger than the sum of its proper divisors (1).

106885388654393 is an equidigital number, since it uses as much as digits as its factorization.

106885388654393 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3583180800, while the sum is 77.

The spelling of 106885388654393 in words is "one hundred six trillion, eight hundred eighty-five billion, three hundred eighty-eight million, six hundred fifty-four thousand, three hundred ninety-three".