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106936433 is a prime number
BaseRepresentation
bin1100101111110…
…11100001110001
321110012221012122
412113323201301
5204333431213
614340004025
72435642012
oct627734161
9243187178
10106936433
11553a9a1a
122b990615
1319201ac6
14102b9009
1595c4d08
hex65fb871

106936433 has 2 divisors, whose sum is σ = 106936434. Its totient is φ = 106936432.

The previous prime is 106936411. The next prime is 106936447. The reversal of 106936433 is 334639601.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 55771024 + 51165409 = 7468^2 + 7153^2 .

It is an emirp because it is prime and its reverse (334639601) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 106936433 - 212 = 106932337 is a prime.

It is a super-2 number, since 2×1069364332 = 22870801405526978, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 106936393 and 106936402.

It is not a weakly prime, because it can be changed into another prime (106936493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53468216 + 53468217.

It is an arithmetic number, because the mean of its divisors is an integer number (53468217).

Almost surely, 2106936433 is an apocalyptic number.

It is an amenable number.

106936433 is a deficient number, since it is larger than the sum of its proper divisors (1).

106936433 is an equidigital number, since it uses as much as digits as its factorization.

106936433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34992, while the sum is 35.

The square root of 106936433 is about 10341.0073493833. The cubic root of 106936433 is about 474.6519082223.

The spelling of 106936433 in words is "one hundred six million, nine hundred thirty-six thousand, four hundred thirty-three".