Base | Representation |
---|---|
bin | 11111100001011111011… |
… | …10010101011001100001 |
3 | 10211112202100202122010201 |
4 | 33300233232111121201 |
5 | 120221223400342032 |
6 | 2145330103025201 |
7 | 141153013532224 |
oct | 17605756253141 |
9 | 3745670678121 |
10 | 1083132434017 |
11 | 388399027017 |
12 | 155b02a3b201 |
13 | 7b1a63734ba |
14 | 3a5d121d5bb |
15 | 1d294c388e7 |
hex | fc2fb95661 |
1083132434017 has 2 divisors, whose sum is σ = 1083132434018. Its totient is φ = 1083132434016.
The previous prime is 1083132434003. The next prime is 1083132434063. The reversal of 1083132434017 is 7104342313801.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 932787024481 + 150345409536 = 965809^2 + 387744^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1083132434017 is a prime.
It is not a weakly prime, because it can be changed into another prime (1083132434117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 541566217008 + 541566217009.
It is an arithmetic number, because the mean of its divisors is an integer number (541566217009).
Almost surely, 21083132434017 is an apocalyptic number.
It is an amenable number.
1083132434017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1083132434017 is an equidigital number, since it uses as much as digits as its factorization.
1083132434017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 37.
Adding to 1083132434017 its reverse (7104342313801), we get a palindrome (8187474747818).
The spelling of 1083132434017 in words is "one trillion, eighty-three billion, one hundred thirty-two million, four hundred thirty-four thousand, seventeen".
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