Base | Representation |
---|---|
bin | 110010011110100010… |
… | …1110110101001101111 |
3 | 101100210112002012200002 |
4 | 1210331011312221233 |
5 | 3234000134032101 |
6 | 121444201254515 |
7 | 10555142243450 |
oct | 1447505665157 |
9 | 340715065602 |
10 | 108399127151 |
11 | 41a765326a7 |
12 | 1901279443b |
13 | a2b6949a73 |
14 | 5364743127 |
15 | 2c467c4d6b |
hex | 193d176a6f |
108399127151 has 4 divisors (see below), whose sum is σ = 123884716752. Its totient is φ = 92913537552.
The previous prime is 108399127139. The next prime is 108399127183. The reversal of 108399127151 is 151721993801.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 108399127151 - 214 = 108399110767 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 108399127096 and 108399127105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (108399727151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7742794790 + ... + 7742794803.
It is an arithmetic number, because the mean of its divisors is an integer number (30971179188).
Almost surely, 2108399127151 is an apocalyptic number.
108399127151 is a deficient number, since it is larger than the sum of its proper divisors (15485589601).
108399127151 is an equidigital number, since it uses as much as digits as its factorization.
108399127151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15485589600.
The product of its (nonzero) digits is 136080, while the sum is 47.
The spelling of 108399127151 in words is "one hundred eight billion, three hundred ninety-nine million, one hundred twenty-seven thousand, one hundred fifty-one".
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