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10909433 is a prime number
BaseRepresentation
bin101001100111…
…011011111001
3202112020221002
4221213123321
510243100213
61025454345
7161504633
oct51473371
922466832
1010909433
116181467
1237a13b5
13234c7b2
14163da53
15e57658
hexa676f9

10909433 has 2 divisors, whose sum is σ = 10909434. Its totient is φ = 10909432.

The previous prime is 10909417. The next prime is 10909441. The reversal of 10909433 is 33490901.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5513104 + 5396329 = 2348^2 + 2323^2 .

It is a cyclic number.

It is not a de Polignac number, because 10909433 - 24 = 10909417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10909396 and 10909405.

It is not a weakly prime, because it can be changed into another prime (10909453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5454716 + 5454717.

It is an arithmetic number, because the mean of its divisors is an integer number (5454717).

Almost surely, 210909433 is an apocalyptic number.

It is an amenable number.

10909433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10909433 is an equidigital number, since it uses as much as digits as its factorization.

10909433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2916, while the sum is 29.

The square root of 10909433 is about 3302.9430815562. The cubic root of 10909433 is about 221.7859650170.

The spelling of 10909433 in words is "ten million, nine hundred nine thousand, four hundred thirty-three".