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109120485217 is a prime number
BaseRepresentation
bin110010110100000010…
…1100111011101100001
3101102122210102222220111
41211220011213131201
53241434321011332
6122043530411321
710612051551262
oct1455005473541
9342583388814
10109120485217
114230673a697
1219194290b41
13a3a0226763
1453d247a969
152c89cb5947
hex1968167761

109120485217 has 2 divisors, whose sum is σ = 109120485218. Its totient is φ = 109120485216.

The previous prime is 109120485107. The next prime is 109120485239. The reversal of 109120485217 is 712584021901.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104923518561 + 4196966656 = 323919^2 + 64784^2 .

It is an emirp because it is prime and its reverse (712584021901) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 109120485217 - 215 = 109120452449 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 109120485217.

It is not a weakly prime, because it can be changed into another prime (109120485277) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54560242608 + 54560242609.

It is an arithmetic number, because the mean of its divisors is an integer number (54560242609).

Almost surely, 2109120485217 is an apocalyptic number.

It is an amenable number.

109120485217 is a deficient number, since it is larger than the sum of its proper divisors (1).

109120485217 is an equidigital number, since it uses as much as digits as its factorization.

109120485217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 40.

The spelling of 109120485217 in words is "one hundred nine billion, one hundred twenty million, four hundred eighty-five thousand, two hundred seventeen".