Base | Representation |
---|---|
bin | 1101000010111… |
… | …01101001011001 |
3 | 21121220220020222 |
4 | 12201131221121 |
5 | 211003413411 |
6 | 14505325425 |
7 | 2466120611 |
oct | 641355131 |
9 | 247826228 |
10 | 109435481 |
11 | 56856551 |
12 | 30796875 |
13 | 1989842c |
14 | 10769a41 |
15 | 991a4db |
hex | 685da59 |
109435481 has 2 divisors, whose sum is σ = 109435482. Its totient is φ = 109435480.
The previous prime is 109435457. The next prime is 109435493. The reversal of 109435481 is 184534901.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 101505625 + 7929856 = 10075^2 + 2816^2 .
It is an emirp because it is prime and its reverse (184534901) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 109435481 - 214 = 109419097 is a prime.
It is a super-2 number, since 2×1094354812 = 23952249003402722, which contains 22 as substring.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (109435451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54717740 + 54717741.
It is an arithmetic number, because the mean of its divisors is an integer number (54717741).
Almost surely, 2109435481 is an apocalyptic number.
It is an amenable number.
109435481 is a deficient number, since it is larger than the sum of its proper divisors (1).
109435481 is an equidigital number, since it uses as much as digits as its factorization.
109435481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 35.
The square root of 109435481 is about 10461.1414769135. The cubic root of 109435481 is about 478.3209287765.
The spelling of 109435481 in words is "one hundred nine million, four hundred thirty-five thousand, four hundred eighty-one".
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