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10959340793 is a prime number
BaseRepresentation
bin10100011010011101…
…00100010011111001
31001021202221012021212
422031032210103321
5134421042401133
65011252412505
7535403600612
oct121516442371
931252835255
1010959340793
114714297a45
12215a317135
13105868ca4b
1475d728c09
1544220c148
hex28d3a44f9

10959340793 has 2 divisors, whose sum is σ = 10959340794. Its totient is φ = 10959340792.

The previous prime is 10959340789. The next prime is 10959340811. The reversal of 10959340793 is 39704395901.

10959340793 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9479553769 + 1479787024 = 97363^2 + 38468^2 .

It is an emirp because it is prime and its reverse (39704395901) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10959340793 - 22 = 10959340789 is a prime.

It is a super-2 number, since 2×109593407932 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10959340753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5479670396 + 5479670397.

It is an arithmetic number, because the mean of its divisors is an integer number (5479670397).

Almost surely, 210959340793 is an apocalyptic number.

It is an amenable number.

10959340793 is a deficient number, since it is larger than the sum of its proper divisors (1).

10959340793 is an equidigital number, since it uses as much as digits as its factorization.

10959340793 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 918540, while the sum is 50.

The spelling of 10959340793 in words is "ten billion, nine hundred fifty-nine million, three hundred forty thousand, seven hundred ninety-three".