Base | Representation |
---|---|
bin | 11111111101001100011… |
… | …00000001111011010001 |
3 | 10212222010211210201200220 |
4 | 33332212030001323101 |
5 | 120442203214110303 |
6 | 2200225542103253 |
7 | 142220404036041 |
oct | 17764614017321 |
9 | 3788124721626 |
10 | 1098004831953 |
11 | 393730114787 |
12 | 15897371ab29 |
13 | 7c706633373 |
14 | 3b202509721 |
15 | 1d865745053 |
hex | ffa6301ed1 |
1098004831953 has 32 divisors (see below), whose sum is σ = 1532336351616. Its totient is φ = 698602065408.
The previous prime is 1098004831933. The next prime is 1098004831991. The reversal of 1098004831953 is 3591384008901.
It is not a de Polignac number, because 1098004831953 - 222 = 1098000637649 is a prime.
It is a super-2 number, since 2×10980048319532 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1098004831896 and 1098004831905.
It is not an unprimeable number, because it can be changed into a prime (1098004831933) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25175101 + ... + 25218677.
It is an arithmetic number, because the mean of its divisors is an integer number (47885510988).
Almost surely, 21098004831953 is an apocalyptic number.
It is an amenable number.
1098004831953 is a deficient number, since it is larger than the sum of its proper divisors (434331519663).
1098004831953 is a wasteful number, since it uses less digits than its factorization.
1098004831953 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47953.
The product of its (nonzero) digits is 933120, while the sum is 51.
The spelling of 1098004831953 in words is "one trillion, ninety-eight billion, four million, eight hundred thirty-one thousand, nine hundred fifty-three".
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