Search a number
-
+
10998068253 = 33666022751
BaseRepresentation
bin10100011111000100…
…10011010000011101
31001101110210202101020
422033202103100131
5140011001141003
65015154434353
7536354015634
oct121742232035
931343722336
1010998068253
114734139507
12216b2929b9
1310636cc2c3
1476492a51b
1544580bd53
hex28f89341d

10998068253 has 4 divisors (see below), whose sum is σ = 14664091008. Its totient is φ = 7332045500.

The previous prime is 10998068233. The next prime is 10998068267. The reversal of 10998068253 is 35286089901.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10998068253 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10998068196 and 10998068205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10998068203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1833011373 + ... + 1833011378.

It is an arithmetic number, because the mean of its divisors is an integer number (3666022752).

Almost surely, 210998068253 is an apocalyptic number.

It is an amenable number.

10998068253 is a deficient number, since it is larger than the sum of its proper divisors (3666022755).

10998068253 is an equidigital number, since it uses as much as digits as its factorization.

10998068253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3666022754.

The product of its (nonzero) digits is 933120, while the sum is 51.

The spelling of 10998068253 in words is "ten billion, nine hundred ninety-eight million, sixty-eight thousand, two hundred fifty-three".

Divisors: 1 3 3666022751 10998068253