11000000041 has 4 divisors (see below), whose sum is σ = 11354838784. Its totient is φ = 10645161300.

The previous prime is 11000000021. The next prime is 11000000057. The reversal of 11000000041 is 14000000011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14000000011 = 2269 ⋅6170119.

It is not a de Polignac number, because 11000000041 - 2²⁷ = 10865782313 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10999999970 and 11000000033.

It is not an unprimeable number, because it can be changed into a prime (11000000021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 177419325 + ... + 177419386.

It is an arithmetic number, because the mean of its divisors is an integer number (2838709696).

Almost surely, 2^11000000041 is an apocalyptic number.

It is an amenable number.

11000000041 is a deficient number, since it is larger than the sum of its proper divisors (354838743).

11000000041 is an equidigital number, since it uses as much as digits as its factorization.

11000000041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 354838742.

The product of its (nonzero) digits is 4, while the sum is 7.

Adding to 11000000041 its reverse (14000000011), we get a palindrome (25000000052).

The spelling of 11000000041 in words is "eleven billion, forty-one", and thus it is an aban number and an uban number.