110000009963 has 2 divisors, whose sum is σ = 110000009964. Its totient is φ = 110000009962.

The previous prime is 110000009953. The next prime is 110000010017. The reversal of 110000009963 is 369900000011.

It is a weak prime.

It is an emirp because it is prime and its reverse (369900000011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110000009963 - 2¹⁰ = 110000008939 is a prime.

It is a super-2 number, since 2×110000009963² (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (110000009953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000004981 + 55000004982.

It is an arithmetic number, because the mean of its divisors is an integer number (55000004982).

Almost surely, 2^110000009963 is an apocalyptic number.

110000009963 is a deficient number, since it is larger than the sum of its proper divisors (1).

110000009963 is an equidigital number, since it uses as much as digits as its factorization.

110000009963 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 29.

Adding to 110000009963 its reverse (369900000011), we get a palindrome (479900009974).

The spelling of 110000009963 in words is "one hundred ten billion, nine thousand, nine hundred sixty-three".