110000012112019 has 2 divisors, whose sum is σ = 110000012112020. Its totient is φ = 110000012112018.

The previous prime is 110000012111989. The next prime is 110000012112047. The reversal of 110000012112019 is 910211210000011.

It is a strong prime.

It is an emirp because it is prime and its reverse (910211210000011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110000012112019 - 2³⁵ = 109965652373651 is a prime.

It is a super-3 number, since 3×110000012112019³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 110000012111987 and 110000012112005.

It is not a weakly prime, because it can be changed into another prime (110000012112059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000006056009 + 55000006056010.

It is an arithmetic number, because the mean of its divisors is an integer number (55000006056010).

Almost surely, 2^{110000012112019} is an apocalyptic number.

110000012112019 is a deficient number, since it is larger than the sum of its proper divisors (1).

110000012112019 is an equidigital number, since it uses as much as digits as its factorization.

110000012112019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 19.

The spelling of 110000012112019 in words is "one hundred ten trillion, twelve million, one hundred twelve thousand, nineteen".