1100001000953 has 2 divisors, whose sum is σ = 1100001000954. Its totient is φ = 1100001000952.

The previous prime is 1100001000883. The next prime is 1100001001061. The reversal of 1100001000953 is 3590001000011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 876850578409 + 223150422544 = 936403^2 + 472388^2 .

It is an emirp because it is prime and its reverse (3590001000011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100001000953 is a prime.

It is not a weakly prime, because it can be changed into another prime (1100001002953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550000500476 + 550000500477.

It is an arithmetic number, because the mean of its divisors is an integer number (550000500477).

Almost surely, 2^{1100001000953} is an apocalyptic number.

It is an amenable number.

1100001000953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100001000953 is an equidigital number, since it uses as much as digits as its factorization.

1100001000953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135, while the sum is 20.

Adding to 1100001000953 its reverse (3590001000011), we get a palindrome (4690002000964).

The spelling of 1100001000953 in words is "one trillion, one hundred billion, one million, nine hundred fifty-three", and thus it is an aban number.