Base | Representation |
---|---|
bin | 10000000000011101001… |
… | …010110110100101110011 |
3 | 10220011021221222012001022 |
4 | 100000131022312211303 |
5 | 121010300224341313 |
6 | 2201200011130055 |
7 | 142321023221141 |
oct | 20003512664563 |
9 | 3804257865038 |
10 | 1100001012083 |
11 | 394564992426 |
12 | 15923014392b |
13 | 7c964070b3c |
14 | 3b35168c591 |
15 | 1d930b00c08 |
hex | 1001d2b6973 |
1100001012083 has 2 divisors, whose sum is σ = 1100001012084. Its totient is φ = 1100001012082.
The previous prime is 1100001012053. The next prime is 1100001012161. The reversal of 1100001012083 is 3802101000011.
It is a weak prime.
It is an emirp because it is prime and its reverse (3802101000011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1100001012083 - 216 = 1100000946547 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100001012053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550000506041 + 550000506042.
It is an arithmetic number, because the mean of its divisors is an integer number (550000506042).
Almost surely, 21100001012083 is an apocalyptic number.
1100001012083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100001012083 is an equidigital number, since it uses as much as digits as its factorization.
1100001012083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1100001012083 its reverse (3802101000011), we get a palindrome (4902102012094).
The spelling of 1100001012083 in words is "one trillion, one hundred billion, one million, twelve thousand, eighty-three".
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