Base | Representation |
---|---|
bin | 10100011111010011… |
… | …01101110011110001 |
3 | 1001101121110111201111 |
4 | 22033221231303301 |
5 | 140012000341032 |
6 | 5015304233321 |
7 | 536406362611 |
oct | 121751556361 |
9 | 31347414644 |
10 | 11000012017 |
11 | 4735246925 |
12 | 216ba6b841 |
13 | 1063c2cc67 |
14 | 764cb4a41 |
15 | 445a92c47 |
hex | 28fa6dcf1 |
11000012017 has 2 divisors, whose sum is σ = 11000012018. Its totient is φ = 11000012016.
The previous prime is 11000011973. The next prime is 11000012021. The reversal of 11000012017 is 71021000011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10867854001 + 132158016 = 104249^2 + 11496^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000012017 - 27 = 11000011889 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11000011988 and 11000012006.
It is not a weakly prime, because it can be changed into another prime (11000018017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500006008 + 5500006009.
It is an arithmetic number, because the mean of its divisors is an integer number (5500006009).
Almost surely, 211000012017 is an apocalyptic number.
It is an amenable number.
11000012017 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000012017 is an equidigital number, since it uses as much as digits as its factorization.
11000012017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14, while the sum is 13.
Adding to 11000012017 its reverse (71021000011), we get a palindrome (82021012028).
The spelling of 11000012017 in words is "eleven billion, twelve thousand, seventeen".
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