Base | Representation |
---|---|
bin | 11001000000101101101100… |
… | …001111011011000000001011 |
3 | 112102110220210200220200020012 |
4 | 121000231230033123000023 |
5 | 103404220424142244242 |
6 | 1025541223252022135 |
7 | 32112153036423416 |
oct | 3100555417330013 |
9 | 472426720820205 |
10 | 110000223399947 |
11 | 3205a918455951 |
12 | 1040694430194b |
13 | 494bc9065c58a |
14 | 1d24079894b7d |
15 | cab559140282 |
hex | 640b6c3db00b |
110000223399947 has 2 divisors, whose sum is σ = 110000223399948. Its totient is φ = 110000223399946.
The previous prime is 110000223399943. The next prime is 110000223400049. The reversal of 110000223399947 is 749993322000011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110000223399947 - 22 = 110000223399943 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 110000223399895 and 110000223399904.
It is not a weakly prime, because it can be changed into another prime (110000223399943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000111699973 + 55000111699974.
It is an arithmetic number, because the mean of its divisors is an integer number (55000111699974).
Almost surely, 2110000223399947 is an apocalyptic number.
110000223399947 is a deficient number, since it is larger than the sum of its proper divisors (1).
110000223399947 is an equidigital number, since it uses as much as digits as its factorization.
110000223399947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 734832, while the sum is 50.
Adding to 110000223399947 its reverse (749993322000011), we get a palindrome (859993545399958).
The spelling of 110000223399947 in words is "one hundred ten trillion, two hundred twenty-three million, three hundred ninety-nine thousand, nine hundred forty-seven".
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