Base | Representation |
---|---|
bin | 1010000000010010010011… |
… | …1000010111010010110110 |
3 | 1102221121000000002212000000 |
4 | 2200010210320113102312 |
5 | 2420211030140002220 |
6 | 35221202150332130 |
7 | 2213503666162641 |
oct | 240044470272266 |
9 | 42847000085000 |
10 | 11000030000310 |
11 | 35610a518a65a |
12 | 1297a6795a046 |
13 | 61a3b56c9210 |
14 | 2a0593544a58 |
15 | 141209133390 |
hex | a0124e174b6 |
11000030000310 has 896 divisors, whose sum is σ = 33576926423040. Its totient is φ = 2575980029952.
The previous prime is 11000030000291. The next prime is 11000030000327. The reversal of 11000030000310 is 1300003000011.
It is a super-2 number, since 2×110000300003102 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (9).
It is a junction number, because it is equal to n+sod(n) for n = 11000030000292 and 11000030000301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 447 ways as a sum of consecutive naturals, for example, 30640751911 + ... + 30640752269.
It is an arithmetic number, because the mean of its divisors is an integer number (37474248240).
Almost surely, 211000030000310 is an apocalyptic number.
11000030000310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 11000030000310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16788463211520).
11000030000310 is an abundant number, since it is smaller than the sum of its proper divisors (22576896422730).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11000030000310 is a wasteful number, since it uses less digits than its factorization.
11000030000310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 616 (or 601 counting only the distinct ones).
The product of its (nonzero) digits is 9, while the sum is 9.
Adding to 11000030000310 its reverse (1300003000011), we get a palindrome (12300033000321).
The spelling of 11000030000310 in words is "eleven trillion, thirty million, three hundred ten", and thus it is an aban number.
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