Base | Representation |
---|---|
bin | 11001000000101110011010… |
… | …101000011110111001001011 |
3 | 112102110222210221110111120101 |
4 | 121000232122220132321023 |
5 | 103404224022420041134 |
6 | 1025541432414110231 |
7 | 32112211240150264 |
oct | 3100563250367113 |
9 | 472428727414511 |
10 | 110001001721419 |
11 | 3206018782a336 |
12 | 10406b20aab377 |
13 | 494c085992023 |
14 | 1d24110db996b |
15 | cab5a2633e14 |
hex | 640b9aa1ee4b |
110001001721419 has 2 divisors, whose sum is σ = 110001001721420. Its totient is φ = 110001001721418.
The previous prime is 110001001721399. The next prime is 110001001721441. The reversal of 110001001721419 is 914127100100011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110001001721419 is a prime.
It is a super-2 number, since 2×1100010017214192 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110001701721419) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000500860709 + 55000500860710.
It is an arithmetic number, because the mean of its divisors is an integer number (55000500860710).
Almost surely, 2110001001721419 is an apocalyptic number.
110001001721419 is a deficient number, since it is larger than the sum of its proper divisors (1).
110001001721419 is an equidigital number, since it uses as much as digits as its factorization.
110001001721419 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 28.
The spelling of 110001001721419 in words is "one hundred ten trillion, one billion, one million, seven hundred twenty-one thousand, four hundred nineteen".
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